Author:
sashok63

Language:
C/C++

Upload:
7:57 AM 04/13/2024

Download

Platform
Unix/linux etc.

Difficulty:
2.1

Quality:
3.8

Arch:
x86-64

Description

This is my first crackme, I hope it wasn't too easy and interesting)))

• Comments
• Solutions

femega on 11:45 AM 04/16/2024: Wow. An amazing crackme by sashahuy. Thanks!

Emanon on 10:39 PM 04/16/2024: I "solved it" but am ways from fully understanding it.

mikky on 4:29 PM 04/18/2024: Nice.password sha256:2F7728EE002DE74333F45B123BF0588D00FF5FF27E95DE4B59CE24D10D0BD8CE

OpaxIV on 5:20 PM 04/19/2024: Can someone give me a hint? I am currently at fun3() and just don't understand what is going on in the CONCAT function. I know some C, Python, Java so it is more about the overall logic. thanks in advance

OpaxIV on 5:22 PM 04/19/2024: * for context, this is the part I mean: ``` local_10 = *(long *)(in_FS_OFFSET + 0x28); local_48 = (ulong)CONCAT14(input_string[1] == **(char **)(param_3 + 0x30), (uint)(*input_string == **(char **)(param_2 + 0x10))); local_40 = (ulong)CONCAT14(input_string[3] == **(char **)(param_5 + 0x20), (uint)(input_string[2] == **(char **)(param_4 + 0x10))); local_38 = (ulong)CONCAT14(input_string[5] == **(char **)(param_7 + 8), (uint)(input_string[4] == **(char **)(param_6 + 0x30))); local_30 = (ulong)CONCAT14(input_string[7] == **(char **)(param_9 + 0x20), (uint)(input_string[6] == **(char **)(param_8 + 0x38))); local_28 = (ulong)CONCAT14(input_string[9] == **(char **)(param_11 + 0x28), (uint)(input_string[8] == **(char **)(param_10 + 0x18))); local_20 = (ulong)CONCAT14(input_string[0xb] == **(char **)(param_13 + 0x38), (uint)(input_string[10] == **(char **)(param_12 + 0x10))); ```

OpaxIV on 6:44 PM 04/19/2024: Managed to do it. Please ignore my comments.

You must me logged to submit a solution