Author:
MiWix7

Language:
C/C++

Upload:
10:35 AM 01/04/2024

Download

Platform
Windows

Difficulty:
3.2

Quality:
4.0

Arch:
x86

Description

My First CrackMe :3 I don't know exactly how difficult it is, try it and find out)

• Comments
• Solutions

GhostmaneX on 11:57 AM 01/05/2024: This is the key - 116110120122112114122112112118 i have put an breakpoint where the cmp is, { cmp esi, dword ptr ss:[ebp-0x48] }

bingies on 5:41 PM 01/05/2024: Note: User string length must be equal to 0x1e

dev0 on 9:17 PM 01/05/2024: @GhostmaneX That key works because the result from running "vol c:" on your machine is probably "Volume Serial Number is B628-C8A2"

Burtson on 4:26 PM 01/06/2024: not really hard, for a beginner like me, it took about 20-35 minutes!

obada8 on 3:36 AM 01/10/2024: I'm begginner in this and this is my first ever crack me solver lol and i solve it, by change address 007A1834 to je and address 007A1854 to jmp

blockslesson on 2:42 PM 01/11/2024: key length is 24 get key python code : key = '' for i in UUID: key += str((i*2)+110) print(key)

justAuser on 9:34 AM 03/09/2024: @blocklesson - how did you get to that algo? I searched for it and could not find it.

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