Author:
very_n00by

Language:
C/C++

Upload:
5:34 AM 09/27/2022

Download

Platform
Windows

Difficulty:
1.8

Quality:
3.5

Arch:
x86-64

Description

This crackme requires a random number from you. This number is then used to generate a new secret number. Find out how this secret number is generated and then calculate it yourself. Type it into the program to check if you're answer/thinking is correct. This is my very first crackme and I'm a beginner at disassembly. So after disassembling it I think it looks quite messy, and hard. But maybe it's not .. Good luck! :)

• Comments
• Solutions

JMac2 on 12:43 AM 11/28/2022: Not to hard if you follow to conclusion, to make people do a little more you should ask for code to calculate the secret number. Anyways my test was enter 20 secret number is 6765, 45 with a secret number of 1134903170

coquee_ on 8:44 PM 12/12/2022: I only had the too small/too big msg, but cracked anyways good crackme :)

bkah on 3:53 AM 02/15/2023: good crackme for beginners, good job.

BigFantaser on 4:22 PM 03/12/2023: Is it okay that i just patched jnz to jz? Can i count this as soultion? Sorry for dumb question, im just noob in RE.

0x4C454F on 11:14 PM 03/13/2023: Italian guy ;)

featherfx on 12:10 AM 03/22/2023: //n is the number you enter 10-50 in this case, this just calculates the nth term in the fibonacci sequence //eg n=10 1 1 2 3 5 8 13 21 34 55 === 55 is the secret code for 10 === if n=11 then 55 + 34 = 89 and so on a so forth int fibn(int n) { if(n

featherfx on 12:11 AM 03/22/2023: int fibn(int n) { if(n

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