Well i think ur algorithm is broken :)
import random,string
print("12345678" + (random.choice(string.ascii_letters) * 3))
Res :
12345678ppp
12345678ccc
12345678(any random character)
....
...
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@noobvariable Good job! Be ready for next part :) |
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@pranav i know what you mean, but as i said in hint file : "If i were you i wouldn't use IDA pro because its just make it harder :D the key validation algorithm is just 6 lines but in IDA pro its just too much and complicated." |
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@4epuxa GJ, Be ready for the next part :) |
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@ToMKoL I don't think so man :) take a look at the hint file! |
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@4epuxa Hi, Good job i think you made it! i think it would be great if you submit your solution with tutorial. GJ again! |
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@mohammadali I actually compiled it with MSVC and i dont know why it detected as a malware anyways i can give u the source code if u want! |
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