Author:
SirEnder125

Language:
C/C++

Upload:
6:45 PM 03/01/2023

Download

Platform
Unix/linux etc.

Difficulty:
1.3

Quality:
2.8

Arch:

Description

A pretty simple crackme. Let me know how quickly you can crack it! There is a hidden pin that doesn't come into play until you enter the correct password. Good luck:)

• Comments
• Solutions

redar on 3:08 PM 03/02/2023: Hey, I will be honest with you. This is an elf file and I tried running it on Windows through git bash but it didn't work. Probably have to do some settings for Linux subsystem... Nevermind, it took me 4 mins 20 secs to from the time I unzipped it. IDA showed everything. So let me suppose pass is "crackmes4ever:)" then you get the input. In your "test" method you perform the check, then ask for pin (also you got a typo there in 'Correct! No enter your pin: ') which should be 0x0Fh == 10. I consider it solved and now I comment here... Have a nice one!

SirEnder125 on 6:40 PM 03/02/2023: Very close! 0xF is 15, so you have to input something 15 characters long. Also yes, this is for Linux. I hope I compiled it correctly? :)

SirEnder125 on 6:42 PM 03/02/2023: Sorry about the typo :/ Can I reupload? haha

NisheshTyagi on 5:54 AM 03/04/2023: That was a real good crackme for beginners like me can you create a one for which i can generate a keygen :)

SirEnder125 on 2:33 AM 03/05/2023: Sure! I'll try making one very soon! :)

maango on 7:19 AM 03/05/2023: This was my first reverse engineering on a C/C++ application. I used GDB to crack it and in 15 mins I was able to solve it. During the PIN part, I just did `set $rax=0xf` and it worked! :)

SirEnder125 on 9:42 PM 03/05/2023: Congrats! Glad you were able to solve it! :)

zinosama on 10:30 PM 03/26/2023: i did it this program is the first one i cracked in my life im so excited

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