Share how awesome the crack me was or where you struggle to finish it! Stay polite and do not spoil the solution/flag!
1:38 AM 12/21/2019
ctf_challenges - try to solve a set of ctf problems. xor good luck
0d1n on 3:35 PM 12/26/2019: very easy, Just jumped from 0x0000087cto 0x00000869; 0x:~/Desktop# ./xordemo Need exactly one argument. 0x:~/Desktop# ./xordemo test Jackpot 0x:~/Desktop# ./xordemo testinvalid Jackpot 0x:~/Desktop#
def00x on 3:52 PM 12/29/2019: I found the hex of 'bigbeef1' and 0x20a170c050a1410 ... the first XOR SECRET_PWD should XOR to the latter hex... there is a logic with a counter there... tried a few things with no luck... Any ideas on this one...?
tiencong283 on 4:03 PM 12/29/2019: It should be marked as level 1
def00x on 5:57 PM 12/29/2019: Why rungirl3 still fails???
def00x on 8:35 PM 12/29/2019: yeap.. found it... rungirl34 :)
Verideth on 5:58 AM 12/31/2019: Awesome crackme! Did a bit of learning :-)
FRIEND35 on 4:51 PM 01/11/2020: iihih
vikasgola2015 on 7:38 PM 01/30/2020: could someone help me how did you get the solution? I tried b = bytearray.fromhex('020a170c050a1410') a = bytearray.fromhex('3166656562646162') ai = bytearray() for i in range(8): ai += bytes([a[i]+i]) aib = bytearray() for i in range(8): aib += bytes([ai[i]^b[i]]) flag = bytearray() for i in range(8): flag += bytes([aib[i]-i]) but no luck :-( Am I doing something wrong?
jimsktsmith on 4:35 PM 02/05/2022: key : rungirl34